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Communication Research Solutions Sampling Below, then use the same approach to solve the practice problems below 0.549 moles Ni2(CO3)3 x 297.41g = 163.27 g 1 moles Ni2(CO3)3 Solving from H2CO3 3.45g x 1 mole H2CO3 = 0.0556 moles H2CO3 62.03g 0.0556 moles H2CO3 x 1 moles Ni2(CO3)3 = 0.01854 moles Ni2(CO3)3 3 moles H2CO3 0.01854 moles Ni2(CO3)3 x 297.41g = 5.514 g 1 mole Ni2(CO3)3 Ni is the excess reagent H2CO3 is the limiting reagent 6. 11-3 practice problems continued chemistry answers. Chemistry 11-3 practice problems answers. Answers to c: H2 + Cl2 ---> 2HCl 1:1. It is the limiting reagent. Discussions of numbers of molecules uses numbers that are directly proportional to the number of moles and do not need to be converted. Name Date Class 11—3 Practice Problems 1. Identify the limiting reactant when 1.22 g 8. Identify the limiting reactant when 65.14 g of CaC12 reacts with 74.68 g of Na2CO to produce CaC03 and NaCl. 9. 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